If it's not what You are looking for type in the equation solver your own equation and let us solve it.
-3a^2+13a+10=0
a = -3; b = 13; c = +10;
Δ = b2-4ac
Δ = 132-4·(-3)·10
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-17}{2*-3}=\frac{-30}{-6} =+5 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+17}{2*-3}=\frac{4}{-6} =-2/3 $
| -3(u+7)=-8u+14 | | 3(w+8)+6w=33 | | x+72=92 | | 8x+3(x-3)=35 | | 2y+2(y+7)=-26 | | 7.5(h+3)+10=6.25h | | 6u-13u=42 | | 6x4-9=x | | 20x^2-130=-200 | | 5x^2-38x+42=0 | | 3x-12°=2x+15° | | 10x^2-76x+84=0 | | Y=-1.5x-3.7 | | (x+7)(x+3)=30 | | 1.8(0.07-x)=x^2 | | 4x−15=2x+1 | | 9^x+14=11 | | 8y-5y=-2=8 | | 2.4+x/5=-14.9 | | 4(×-1)=2x+3 | | 2(x-4)=-9+x | | 4x²+16x-9=0 | | 5+5p+4-2p-7+p=22 | | 3x+100+x=180° | | 4x+4=-4x+4 | | 3x+4=-12x-2 | | 12y+39=15 | | 4y+8=-24 | | -2(x)=4x-3 | | -7/8t=7/16 | | 10(1/2x-2)-5=3(x-6)+1 | | 6n+1=35 |